Details are being finalized for the Iowa Faith & Freedom Coalition’s Spring Event which will feature Sen. Rand Paul (R-Kentucky). The event, set to be held on Friday, May 11th, is expected to be attended by more than 600 Iowa activists who will play a foundational role in campaigns this fall. The senator lives in Bowling Green, Kentucky where Rand owned his own ophthalmology practice and performed eye surgery for 18 years. He attended Baylor University and graduated from Duke Medical School. Rand is a member of Lions Clubs International, which is dedicated to preserving sight by providing eyeglasses and surgery to the less fortunate around the world. He has provided free eye surgery to children from around the world through his participation in the Children of the Americas Program.
As a U.S. Senator, Rand Paul has vigorously defended life. He is an original sponsor of the Life at Conception Act, which would put Congress on record defining when life begins and overturn Roe v Wade. He has voted against funding for Planned Parenthood at every opportunity, and fought against the Obamacare mandates on religious institutions. Recently, Sen. Paul has formed an organization, RANDPAC, to promote and support candidates for office. With an objective to change the way that business is done in Washington, he is also a leader of the Tea Party movement in the U.S. Senate.
Invitations to the May 11th event are also being extended to elected officials here in Iowa as well as Fox News contributor and Faith & Freedom Coalition Chairman, Ralph Reed.
The event is set to take place at Point of Grace Church at 305 NE Dartmoor Drive in Waukee, Iowa from 5:30 p.m.-7:30 p.m. For any questions, contact the offices of the Iowa Faith & Freedom Coalition at 515-225-1515.